📅 NSB 2012🎓 HS🔄 Round 12#️⃣ Q4🌟 BONUS✍️ Short Answer
How many real solutions does the following equation have: (x^2 + 1)^2 + 2(x^2 + 1) - 3 = 0 [x squared plus 1 quantity squared plus 2 times open parenthesis x squared plus 1 close parenthesis minus 3 equals zero]?
✔️Answer:ONE
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