📅 NSB 2014🎓 HS🔄 Round 15#️⃣ Q9🌟 BONUS✍️ Short Answer
Evaluate the following definite integral: ∫ from -3 to 0 of √(9 – x^2)dx [the integral from negative three to zero of the square root of open parenthesis nine minus x squared close parenthesis d x]
✔️Answer:9π/4
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